Triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R If ∠P measures 27°, ∠R measures 135°, and r equals 9.5, then which length can be found using the Law of Sines?

a. p
b. r
c. PQ
d. PR

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step-by-step explanation:

answer is : muchas/tipicas

have a nice day!

~recklesschicken

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3