Mathematics, 11.02.2022 14:00 Chris3529

Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot. Step 1: Since 4 squared = 16 and 5 squared = 25 and 16 < 18 < 25, StartRoot 18 EndRoot is between 4 and 5. Step 2: Since 18 is closer to 16, square the tenths closer to 4. 4. 1 squared = 16. 81 4. 2 squared = 17. 64 4. 3 squared = 18. 49 4. 4 squared = 19. 36 Step 3: Since 18. 49 rounds to 18, 4. 3 is the best approximation for StartRoot 18 EndRoot. In which step, if any, did Nolan make an error? In step 1, StartRoot 18 EndRoot is between 4 and 5 becauseStartRoot 18 EndRoot almost-equals 20 and 4 times 5 = 20. In step 2, he made a calculation error when squaring. In step 3, he should have determined which square is closest to 18. Nolan did not make an error.

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Nolan used the following procedure to find an estimate for StartRoot 18 EndRoot. Step 1: Since 4 squ...