Thomas was selling tickets to his school play. The tickets cost $5. 00 for adults and $2. 00 for children. He sold 200 tickets and collected $610. Which system represents the number of adult and child tickets that Thomas sold? x y = 200. 5 x 2 y = 610. X y = 610. 5 x 2 y = 200. X y = 200. X 2 y = 610. X y = 200. 5 x y = 610.

x + y = 200

5x + 2y = 610

There were 130 child tickets sold and 70 adult tickets sold

Step-by-step explanation:

**The selection of solutions is not clear from your question so I have written equations and solved them**

Let x = number of adult tickets sold

Let y = number of child tickets sold

If 200 tickets are sold, then x + y = 200

If the total collected was $610, then 5x + 2y = 610

To solve this, rewrite x + y = 200 making x the subject:  

x = 200 - y

Substitute x = 200 - y into 5x + 2y = 610 and solve for y:

  5(200 - y) + 2y = 610

⇒ 1000 - 5y + 2y = 610

⇒ 1000 - 3y = 610

⇒ 1000 - 610 = 3y

⇒  390 = 3y

⇒ y = 390 ÷ 3 = 130

Now substitute y = 130 into x + y = 200 to find x:

x + 130 = 200

⇒ x = 200 - 130 = 70

Therefore, there were 130 child tickets sold and 70 adult tickets sold.

answer: 12   they all have at least 28 days

step-by-step explanation: haha