Pape 19. 1+2+3+4+5+ ... + 1 = n(n+1)
n
2
(a) i) Show that this formula is true for the sum of the first 8 natural numbers.
ii) Find the sum of the first 400 natural numbers.

i think the answer is b

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function