SOMEONE HELP
PLS EXPLAIN STEP BY STEP WHAT TO DO IM SO CONFUSED

  x = log(33)/(3·log(2))

Step-by-step explanation:

The relevant logarithm relation is ...

  log(a^b) = b·log(a)

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Taking the logarithm of both sides of your equation gives ...

  2^(3x) = 33

  log(2^(3x)) = log(33)

  (3x)·log(2) = log(33)

The coefficient of x is 3·log(2). Dividing by that gives the value of x:

  x = log(33)/(3·log(2))

  x ≈ 1.51851/(3·0.301030) ≈ 1.6814647

step-by-step explanation:

tangent z: 4/3

cosine y: 4/5

cotangent y: 4/3