What is the equation of this trend line? Enter your answers by filling in the boxes.

K = _J + _

K=-2J+28

Step-by-step explanation:

(0,28),(14,0)

0=14m+k

0=14m+78

14m=0-78

14m=-28

m=-28÷14

m=-2

k=-2J+28

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

12/11c

or

12

c

11