Where is the hole for the following function located? X+3
(
f(x)=(x-4)(x+3)
Ox=-3
O y=-3
O x= 3
O y=3

The hole of a function is described as the x-y coordinate wherein the denominator and numerator equates to zero. For the function f(x)= x+3/(x+4)(x+3), the common polynomial given is x-3 which can be equated to zero. Hence, 0 divided 0 means a hole in the function. If x+3 = 0, the hole of the function is at x = -3. ^w^