2. What extraneous solution arises when the equation x + 3 = 2x is solved for
x by first squaring both sides of the equation?
Enter your answer in the box.

x = -3/4

Step-by-step explanation:

I assume the question is

√(x + 3) = 2x

Square both sides.

x + 3 = 4x²

4x² - x - 3 = 0

(4x + 3)(x - 1) = 0

4x + 3 = 0 or x - 1 = 0

x = -3/4 or x = 1

Check solution x = -3/4 in the original equation.

√(x + 3) = 2x

√(-3/4 + 3) = 2(-3/4)

This solution cannot work since the right side is negative, and a square root cannot equal a negative number.

Check solution x = 1 in the original equation.

√(x + 3) = 2x

√(1 + 3) = 2(1)

√4 = 2

2 = 2

Solution x = 1 works.

x = -3/4

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

b. 2 and 4

step-by-step explanation: