Given: △ACE, BD¯¯¯¯¯∥AE¯¯¯¯¯ Prove: BACB=DECD A triangle with vertices labeled as A, C, and E, with base A E. Sides C A and C E contain midpoints B and D, respectively. A line segment parallel to base A E is drawn from point B to D. Angle C A E is labeled as 4 and angle C E A is labeled as 3. Angle C B D is labeled as 1 and angle C D B is labeled as 2. Drag an expression or phrase to each box to complete the proof. StatementReason △ACE, BD¯¯¯¯¯∥AE¯¯¯¯¯Given Response areaCorresponding Angles Postulate △ACE∼△BCDResponse area CACB=CECDDefinition of similar triangles CA=CB+BACE=CD+DESegment Addition Postulate CB+BACB=CD+DECDSubstitution Property of Equality CBCB+BACB=CDCD+DECD Addition of fractions 1+BACB=1+DECDSimplification of fractions Response areaSubtraction Property of Equality