A used car dealership initially prices a car at $12,000. When the car fails to sell, the dealership reduces the prices to $10,500. During a holiday sale, the dealership drops the price of the car an additional 5 percent below the reduced price. To the nearest tenth of a percent, what is the total percent discount from the car's initial price to the holiday sale price?

16.9% to the nearest tenth of a percent

Step-by-step explanation:

First, find the FINAL sale price (after the additional holiday 5% reduction).

If we wish to reduce $10,500 by 5%, that means the final price is 95% of the before price.  

95% = 95/100 = 0.95

So 95% of $10,500 = 0.95 x 10500 = $9,975

To find the total percent discount, we use the percent change formula:

percent change = (difference between the values ÷ original amount) x 100

=  ((12000 - 9975) ÷ 12000) x 100

= 16.875%

So the total percent discount from the car's initial price to the hoiday sale price is 16.9% to the nearest tenth of a percent.

answer: ur mum is gay

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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