This probability distribution shows the typical grade distribution for a Geometry
course with 35 students.
Grade
А
B
C D
F
Frequency 5
10
15
3
2
Find the probability that a student earns a
grade of A, B, or C.
p = [?]
Enter a decimal rounded to the nearest hundredth.

0.714

Step-by-step explanation:

P(A or B or C) = P(A) + P(B) + P(C)

=(5/35)+(10/35)+(15/35)

=25/35

=0.714

step-by-step explanation:

your mom

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116