The angle of elevation to a nearby tree from a point on the ground is measured to be 69^{\circ} ∘
. How tall is the tree if the point on the ground is 35 feet from the tree? Round your answer to the nearest tenth of a foot if necessary.

The tree is approximately 91.2 ft tall.

Step-by-step explanation:

Hi there!

We're told:

- angle of elevation = 69 degrees

- there is a point 35 feet from the tree

If we were to draw this out, it would appear to be a right angle triangle. See the picture below.

Now, to solve for the height of the tree, we can use the sine law:

where a and b are two sides of a right triangle and A and B are the respective opposite angles

Let the height of the tree = h.

Side h is opposite of the angle measuring 69 degrees:

Let the angle opposite of the side measuring 35 feet = A.

Because the sum of a triangle's interior angles is 180 degrees, we know that A=180-90-69=21 degrees.

Use the sine law:

Therefore, the tree is approximately 91.2 ft tall.

I hope this helps!

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

step-by-step explanation: