I need help pls this is for today

2a. The max number of turning point on a polynomial with the m degree is m-1

In this case the answer is 3 because 4-1=3

2b.First, let apply Descartes Rule of Signs to find possible real zeroes.

First, find number of sign changes. There is one sign change so there is possible of one positive zero.

Now there is 2 sign changes so at max, we have 2 negative zeroes

So we have 1+2=3 possible real zeroes at max.

Now plug in (-x) a see how many sign changes occur here.

2c. Since the degree is 4, the zeroes at most will be 4. That is not always thr case if we have multiplicity of zero but at most, we will have four zeroes.

2d. Since this a even degree polynomial and it's negative,

as we go to the left and right, we will approach negative infinity

2e.Look at graph above

We have 3 zeroes like we said, there is 3 turning points, the end behavior is right so it like we did good.

2f. as x approaches -1 from the left, it increases to zero.

a=r

d=q

c=p

b=s

hope this !

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.