Mathematics, 27.01.2022 23:00 jwbri

Prove the following using complex numbers. $\footnotesize \rm\displaystyle \rm \frac{\sin((2n+1)\theta)}{(2n+1)\sin(\theta)} = \prod_{r=1}^n \left( 1-\frac{\sin^2(\theta)}{\sin^2\left(\frac{r\pi}{(2n+1)}\right)} \right )$

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Prove the following using complex numbers.
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