The drop that riders experience on Dr. Doom's Free Fall can be modeled by the quadratic function, where h is height in meters and t is time in seconds. Show your work for each parts. Part A: What is the starting height of riders?

Part B: According to the function, when will the height of the riders equal 0?

Part C: Will the height ever actually equal 0? Why or why not?

  A. 39 m

  B. approximately t = 1.756 seconds

  C. maybe; it depends on the design of the ride (and the accuracy of the model)

Step-by-step explanation:

The "starting" value is generally understood to be the value when t=0. Here, we have ...

  h(0) = -9.8·0² -5·0 +39 = 0 +0 +39 = 39

The starting height is 39 meters.

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The height of the riders will be 0 for the value of t that makes h(t) = 0. That is the solution to the equation ...

  -9.8t² -5t +39 = 0

Using the quadratic formula, the solution for ax²+bx+c = 0 is ...

  x = (-b±√(b²-4ac))/(2a) . . . . . . . we have a=-9.8, b=-5, c=39

Then the time can be found to be ...

  t = (-(-5)±√((-5)²-4(-9.8)(39)))/(2(-9.8)) = (-5±√1553.8)/19.6

  t ≈ (-5 ± 39.4183)/19.6 ≈ {-2.266, +1.756}

Only the positive solution is of interest, so ...

  t ≈ 1.756 . . . seconds

The height of the riders will equal 0 about 1.756 seconds after the start of the ride.

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To the extent that the given function accurately models the height of a rider, there does exist a time at which the rider's height is actually zero. There may be any of a number of reasons why the rider's height may not be zero:

here is your mark brainliest

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841