A linear function crosses the x-axis when x= -3 and the y axis when y = 12 Write the equation of the line.

y = m x + b       equation of straight line

If x = 0    then

12 = b    and we have y = m x + 12

If y - 0 then

0 = m (-3) + 12   and m = 4

y = 4 x + 12 is the final equation

Check:

let x = -3    then y = 0      as specified

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.