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Step-by-step explanation:

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Option B

The answer is 15

Step-by-step explanation:

AC = √[(x₂ – x₁)² + (y₂ – y₁)²]

Now,

x₁ = 2

x₂ = 14

y₁ = 10

y₂ = 1

AC = √[(x₂ – x₁)² + (y₂ – y₁)²]

AC = √[(14 – 2)² + (1 – 10)²]

AC = √[(12)² + (-9)²]

AC = √(144 + 81)

AC = √225

AC = 15 units

Thus, The distance between A(2, 10) and C(14, 1) is 15 units

-TheUnknownScientist 72

d (5 x (-20)) * (100 x (0.7))

step-by-step explanation:

5÷1/100 * -.7 *-20

copy dot flip

5*100 * -.7 *-20

rearrange

5*-20   * 100 *-.7

-100   *-70

7000