Help me please Delta math.

6

Step-by-step explanation:

We're given a piecewise function with two different equations.

One has a domain of all real numbers but 1, whereas the other has the domain of only 1. If you look at the second function, it explicitly states that it is true only when x is one. So when x is one, f(x) is 6.

So f(1) = 6

1/800 is the right answer

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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