Which of the following has a solution set of {x | x = 0}? (x + 1 < -1) ∩ (x + 1 < 1)

(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)

(x + 1 < 1) ∩ (x + 1 > 1)

Step-by-step explanation:

middle options

(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)

if you work do the sides separately you get

which reduces nicely to

{x | x = 0}

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.