Please. help.

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1)

√50

50=2·5²

The 5s can be taken out to get 5√2

2)

√24

24=2³·3

Two 2s can be taken out to get 2√6

3)

√192

192=2⁶·3

We can take the 2s out to get 8√3

4)

√169

169=13²

The 13s can be taken out to get 13

5)

√147

147=3·7²

The 7s can be taken out to get 7√3

6)

√(13/49)

√13/√49

13 is prime, 49=7²

(√13)/7

7)

√(6/27)

√6/√27

6=2·3 and 27=3³

Two 3s can be taken out to get √6/3√3

√6 can be rewritten as √2·√3

In (√2·√3)/3√3 the √3s cancel leaving √2/3

8)

3/√6

In fractions you can multiply and divide by x/x

In this case, x=√6

3√6/(√6·√6)

3√6/6

6=3·2 and the 3s cancel out leaving √6/2

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure