HELP PLEASE!! Write an equation of the line that passes through (−2, 4) and is parallel to y = −3x + 4.

at x=-2,

y=-3(-2)+4

y=10

at y=4,

4=-3x+4

3x=4-4

x=0

(-2,4),(0,10)

gradiant=-3

y-4=-3(x-(-2))

y-4=-3x-6

y=-3x-2

215.92 dollars is the answer

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180