IS it possible for a triangle to have sides with the given lengths 1. 5in., 8in., 15.,

2. 10cm, 12cm, 20cm

Remember, in order for a triangle to be real, the sum of its two shortest sides must be greater than the longest side.

Here, we have

5 in, 8 in, 15 in.

5+8=13 in, and 13 isn't larger than 15, so it's not possible for a triangle to have sides with these lengths.

Let's try the next one:

10 cm, 12 cm, 20 cm.

10+12=22

22>20, so it possible to have a triangle with the given lengths.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

the answer is a

step-by-step explanation: