A curve has equation
y = x²(x - 2)
Work out the gradient of the curve at the point (3,9).

y = x^2 (x - 2) = x^3 - 2 x^2

dy/dx = 3 x^2 - 4 x

At x = 3  dy/dx = 3 * 9 - 4 * 3 = 15  The slope (gradient) of the curve

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !