![4r-s=2s-6r\implies 10r-s=2s\implies 10r=3s\implies r=\cfrac{3s}{10} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 2nd equation}}{\left[ 4\left( \frac{3s}{10} \right)-s \right]+\left[ 6\left( \frac{3s}{10} \right)+7s \right]}=180\implies \left( \cfrac{12s}{10}-s \right)+\left( \cfrac{18s}{10}+7s \right)=180 \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{10}~\hfill }{10\left[ \left( \cfrac{12s}{10}-s \right)+\left( \cfrac{18s}{10}+7s \right) \right]=10(180)}](/tpl/images/2622/4548/a8ba0.png)
Solve for the values of r and s.
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Mathematics, 16.01.2022 04:30 kaseykrueger47
Solve for the values of r and s.
Answers: 1
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