In a mathematics test given to 15 students, the following marks (out of 100) se recorded. Find the mean 41,39,48,52,46,62,54,40,96,52.98,40 ,42,52.60

54.8

Step-by-step explanation:

41+39+48+52+46+62+54+40+96+52+98+40+42+52+60 = 822

822/15= 54.8

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Hey there! I'll try to provide you with my best answer.

51.198 but if the question asks approximation then it's 51 .

In order to find we the mean, we add them all and divide the total by how many numbers there were. So,

(41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52.98 + 40 + 42 + 52.60)/13

= 665.58/13

= 51.198

Approximately its 51

Hope it helps! ^^

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

step-by-step explanation: