During a sale, a store offered a 30% discount on a camera that originally sold for $810. After the sale, the discounted price of the camera was marked up by 30%. To the nearest whole number, what percent of the original price was the price after markup?

Start with with original price and find 30% of that price:

    30% of 810: (0.30)(810) = 243

Now take that 30% away:

   810 - 243 = 567

That's the sale price: $567

Find 30% of the sale price:

    30% of 567: (0.30)(567) = 170.10

Now add that 30% on to the sale price:

   567 + 1701.0 = 737.10

The final price described is $737.10.

Now we need to relate that final price to the original price:

   737.10 ÷ 810 = 0.91

This means that the final price is 91% of the original price.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3