PLEASE HELP i am desperate. Zack is building a model sailboat. The mast will have two inches of height below the base of the main sail, as shown in the diagram below. He wants the base of the sail to have a length of 11 inches and angle S to measure 49 degrees.
A) Write an equation that can be used to find the length of the side of the triangular sail opposite angle S.
B) Find the length of the side of the triangle opposite angle S, to the nearest tenth.
C) What will be the height of the mast, to the nearest tenth?

A)  x = 11 tan 49°

B) 12.7 inches

C) 14.7 inches

Step-by-step explanation:

(refer to attached for reference)

Let the length of the vertical side of the triangular sail be x

recall that for right angle triangle, the following trigonometric relation applies:

tan θ = length of opposite side / length of adjacent side

in our case,

θ = 49°

length of adjacent side = 11 inches

length of opposite side = length of vertical edge of sail = x (which we defined above)

hence we can assemble our formula

tan 49° = x / 11  (rearranging)

x = 11 tan 49°  (Answer for A)

Using a calculator to solve this gives

x = 12.65 inches

x = 12.7 inches (to nearest tenth)   (Answer for B)

The height of the mast is merely the height of the sail plus the 2" length of mast extending below the sail.

Mast height = 12.7" + 2" = 14.7"   (Answer for C)

three-fourths of an hour

36÷48=0.75

0.75=

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.