Replace the * with a monomial so that the result is an identity:(*-5x)(*+5x)=4x^2-25y^2

(2x - 5y)(2x + 5y)

Step-by-step explanation:

1) Consider the Polynomial as such: 4x^2 + 0xy -25y^2

2) Consider also that (4x^2 + 10xy) + (-10xy - 25y^2) would be the best way to arrange the factoring.

3) then you take 2x out from each equation to get: (2x)(2x+10y) (-2y -25y^2)

4) then you take -5y out to get: (2x-5y)(2x+5y)

i dont know

step-by-step explanation:

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.