in triangle pqr, if angle p=x-12, angle q=5x-27, and angle r=2x+3, find c and the measure of each angle

8) x = 27

Angle P = x - 12 (15)

Angle Q = 5x - 27 (108)

Angle R = 2x + 3 (57)

Equation: (x - 12) + (5x - 27) + (2x + 3) = 180

x = 27

9) x = 14

Angle A = 7x - 6 (92)

Angle B = 3x - 5 (37)

Angle C = 4x - 5 (51)

Equation: (7x - 6) + (3x - 5) + (4x - 5) = 180

x = 14

10) x = 20

Angle K = x (20)

Angle L = x + 13 (33)

Angle J = 6x + 7 (127)

Equation: x + (x + 13) + (6x + 7) = 180

x = 20

11) x = 41

Angle Y = x (41)

Angle W = 2x - 5 (77)

Angle X = x + 21 (62)

Equation: x + (2x - 5) + (x + 21) = 180

x = 41

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap