In the given figure triangle ABC, AC=100, CB= 50 , then find the value of x? Please solve me before 10:50 AM.

Step-by-step explanation:

Given that

∆ABC is a right angled triangle

angle B = 90°

BC = 50 units

Hypotenuse (H) = AC

AC = 100 units

We know that

Cos A = Adjacent side to angle A / Hypotenuse

→Cos x = BC / AC

→Cos x = 50/100

→Cos x = 1/2

→Cos x = Cos 60°

.°. x = 60°

Hence, the value of “x” is 60°

also read similar questions: In triangle ABC, E is the midpoint of AC and D is the midpoint of CB. if DF is parallel to BE, find the length of side AB.

Points B, D, and F are midpoints of the sides of triangle ACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale. For my answer I put 32 because df is p...

the answer is c 150

step-by-step explanation: