Which set of ordered pairs does not represent a function? { ( 5 , − 1 ) , ( − 6 , − 7 ) , ( − 5 , − 7 ) , ( 9 , 6 ) } {(5,−1),(−6,−7),(−5,−7),(9,6)} { ( 8 , − 1 ) , ( − 4 , − 1 ) , ( − 6 , 5 ) , ( 4 , − 2 ) } {(8,−1),(−4,−1),(−6,5),(4,−2)} { ( 8 , 6 ) , ( − 1 , 2 ) , ( 8 , − 8 ) , ( 1 , 9 ) } {(8,6),(−1,2),(8,−8),(1,9)} { ( − 1 , 1 ) , ( 7 , − 2 ) , ( − 7 , − 3 ) , ( 0 , − 3 ) } {(−1,1),(7,−2),(−7,−3),(0,−3)} Submit Answer

 { ( 8 , 6 ) , ( − 1 , 2 ) , ( 8 , − 8 ) , ( 1 , 9 ) }

Explanation:

The x coordinate 8 repeats itself for the points (8,6) and (8,-8). This is enough info to see that we don't have a function. A function is only possible when any x value goes to exactly one y value.

answer: i believe its b. if you sound out the sentences that sounds wrong.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.