The length of a rectangle is 2cm less than twice the width. If y represents the width, state the inequality that the area of a rectangle is at least 15cm^2

Here, let width of the rectangle be x cm then length becomes xcm+5cm(length of the rectangle is 5cm longer than width)

Now, we know

Perimeter(p)=2(length+width)

40= 2(x+5+x)

40=2(2x+ 5)

40/2=2x+5

20=2x+5

20–5=2x

15/2=x

x=7.5

Now,

length=x+5=7.5+5=12.5cm

width=x=7.5cm

Therefore length is 12.5cm and width is 7.5cm

a

b

d

step-by-step explanation: