Write the equation of the line that passes through the given point and is parallel to the given line: (2,7); 3x - y = 5

  3x -y = -1

Step-by-step explanation:

The parallel line can have the same x- and y-coefficients. It will have a different constant. The constant can be found using the x- and y-values of the given point to make sure they satisfy the equation.

  3x -y = 3(2) -(7) = -1

The equation of the line is ...

  3x -y = -1

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3