The radiuses of two intersecting circles are 17 and 39. The distance between their centers is 44. Find the length of their common chord

If x is the distance from centre fo the circle, with radius 25cm, to its intersection point with the common chord, x²+24²=25² =>x=7cm.

Distance from this intersecting point to the centre of the other circle=39–7=32cm

Ratio of the sides of the right triangle thus formed is 24:32=3:4. Since 3:4:5 is the basic pythagorean triplet, the radius of the other circle=5*24/3=40cm.

Aliter: radius of the other circle=√32²+24²= 40cm.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: