let r(x) = f(g(h(x))), where h(1) = 2, g(2) = 3, h'(1) = 3, g'(2) = 3, and f '(3) = 6. find r'(1). r'(1) = 36 incorrect: your answer is incorrect.

answer: i don't understand it

step-by-step explanation: sorry

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu

use photo math thats what i use u can scan the problem and it tells u the answer