Carlos cycles for 2 hours at a fast speed, then cycles for 3 more hours at a speed 10 km/h slower than this. If the entire distance travelled is 90 km, find Carlos’ speed in the first two hours of travel.

f=24km/h

Step-by-step explanation:

Alright, here's what we know.

He travels 2 hours at a fast speed, lets call that speed f km/h

He then travels 3 hours at (f-10) km/h

In these 5 hours, he travels 90km

So we have the formula velocity = distance/time. If you don't know where that formula comes from, let me know and I'll explain.

So we have:

d and t are given to us as 90 and 5 respectively

v is going to be his average speed, so we take 2 times the fast speed plus 3 times the slower speed and divide it by 5. This gives us the average speed he traveled over the 5 hours.

2f+3f−30=90  by cancelling the 5's in the denominator and expanding 3(f−10)

5f=120

f=24km/h

So his faster speed is 24 km/h. Let me know if this solution did not make sense to you at any point.

its the fourth option

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

by good luck mark me as brainliest

have a nice day