Mathematics, 23.12.2021 23:40 macyfrakes

Cómo joah puede terminar su trabajo con números complejos X2 -6x+ 10 =10
X2 - 6x = -10
X2 -6x + 9 = -10 +9
(X-3)2 = -1

Answers: 3

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Cómo joah puede terminar su trabajo con números complejos X2 -6x+ 10 =10
X2 - 6x = -10