There were 560 people at a play. The admission price was $2 for adults and $1 for children. The admission receipts were $860.
How many adults and how many children attended?

• For this one we need to split this problem into two equations:

• a (adults) + c (children) = 560

• 2a + c = $860

• Then we substitute 560 - a for c in the second equation.

• Then we plug this into the first equation:

Step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: