3x+y=8
5x+y=10
please help me sir

X = 1

Y = 5

Step-by-step explanation:

we have to figure out what x and y = that make both answers correct

3 x 1 = 3

3 + 5 = 8

That means that the first equation is right with X = 1 and Y = 5

Let's see the second equation

5 x 1 = 5

5 + 5 = 10

That means both equations are right so the answer would be

X = 1 and

Y = 5

Method of Elimination:

Given pair of linear equations are:

3x+y = 8 — — —Eqn(i)

On comparing with a₁x+b₁y+c₁ = 0

Where,

5x+y = 10 — ——Eqn(ii)

On comparing with a₂x+b₂y+c2₂ = 0

Where,

a₁/a₂ = 3/5

b₁/b₂ = 1/1= 1

c₁/c₂ = 8/10=4/5

We have,

a₁/a₂ ≠ b₁/b₂ ≠ c₁/c₂

So, Given pair of linear equations in two variables have a unique solution.

Now,

On Subtracting eqn(ii) from eqn(i) then

3x+y = 8

5x+y = 10

(-)

-2x+0 = -2

⇛-2x = -2

⇛2x = 2

⇛x = 2/2

⇛x = 1

On Substituting the value of x in eqn(i) then

⇛3(1)+y = 8

⇛3+y = 8

⇛y = 8-3

⇛y = 5

Therefore , The solution = (1,5)

Additional comment:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl