The expedition team plan a final practice run to test the range of their communication equipment. One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km. How far apart are the two team members?

We need to sketch the problem first.

Find the size of angle R.

One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.

If se substute 50° of 180 we have

180-50=130°

The distance between the two team members is the missing side.

We know two sides and included angle, so we use the cosine rule.

A2+b2+c2-2bcCosA

= 102+122-(2x10x12xcos130°)

=100+144-(-147.08)

=100+144+147.08

=391.08

A==SQRT391.08

=19.775

19.7km

Step-by-step explanation:

d≈7.07in

step-by-step explanation: