Solve for x and y using method of subsititution y=6x-11
-2x-3y=-7
show ur work

x=2, y=1

Step-by-step explanation:

Given:

y=6x-11

-2x-3y=-7

Substitute y in 2nd equation:

-2x-3y=-7

-2x-3(6x-11)=-7

-2x-18x+33=-7

-20x+33=-7

-20x=-40

x=2

Substitute x in 1st equation:

y=6x-11

y=6(2)-11

y=12-11

y=1

(2, 1)

Step-by-step explanation:

y=6x-11...(1)

-2x-3y=-7...(2)

Subsitute (1) into (2)

-2x-3y=-7

-2x-3(6x-11)=-7

-2x-18x+33=-7

-20x=-40

x=2

Subsitute x=2 into (1)

y=6x-11

y=6(2)-11

y=1

Therefore, the solution of the system is the ordered pair (2, 1)

1 and 0

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.