Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflection of the parent function over the x-axis. Use the sine tool to graph the function.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
PLZ GRAPH IT ON THIS GRAPH THAT I PROVIDED PLZZ HELP ASAP PLZZZ

The graph is shown below.

Explanation:

The midline is y = -3 and the y intercept is (0,-3). This is point A in the diagram below.

The period is pi units, which means that going from midline to peak (or valley) is 1/4 of this distance. So it's pi*(1/4) = pi/4 = 0.79 units approximately from x = 0 to x = 0.79; which is the x coordinate of point B. Point B is one of the infinitely many maximum points. Notice that the vertical distance from A to B is 4 units, which is the amplitude.

Extra info:

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

b

step-by-step explanation:

the word superfluous means unnecessary