Solve. −4<2x−8≤10 Question 1 options: −6

Step 1: 4(2x − 4) = 8 + 2x + 8

Step 2: 6x − 8 = 16 + 2x

Step 3: 6x − 2x = 16 + 8

Step 4: 4x = 24

Step 5: x = 6

Step-by-step explanation:

In which step did the student first make an error and what is the correct step? Step 2; 8x − 4 = 2(6 + x + 6)

Step 2; 8x − 16 = 16 + 2x

Step 3; 6x − 2x = 16 − 8

Step 3; 6x + 2x = 16 + 8

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

96 cm is the answer.