for triangle abc with ab equal to 15cm ac equal to 20cm. Draw mh perpendicular to ab at h, mi perpendicular to ac at i. prove quadrilateral ahmi is a rectangle

step-by-step explanation:

abc

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length