2. Use the power function to calculate the half major axis of the asteroid Vesta, which has an orbital period around the sun of 3.63 years?? Some tings i wrote down:

I have to use keplers law: Kepler's laws say that: T^2 / a^3 = constant
y=1.00027*x^1.499
1.499 same as 1.5 same as 3 halfs
y = t is that year depends on the radius of AE
We use an AE on the ground which is 1 and a 1 year on the ground is 1

go on the tube you might find some information there

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval