Help for 40 points geometry

in triangle SNU

angle U is 180-120 = 60

total angle of triangle is 180°

so, 180-80+60 = 40

angle S and angle P is equal bcs SN and PD are parallel.

so 180-40 = X

X = 140°

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐