1 1.
A random variable X has expected value
and probability distribution as
12
follows:
X
-3
-2
-1
0
1
N
3
f(x)
a
2a
1
1
1
b
сле
b b
2
5
10
5
(a)
(b)
Find the values of a and b.
Find E[X2 + 1].
(8 marks)

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

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step-by-step explanation:

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