answer:
total cost for tiles and paints is $924.
step-by-step explanation:
we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.
the paint will be required for 4 walls and ceiling.
let us find area of walls and ceiling.
![\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)](/tex.php?f=\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3))
![\text{area of walls and ceiling}=1200+90+120](/tex.php?f=\text{area of walls and ceiling}=1200+90+120)
![\text{area of walls and ceiling}=1410](/tex.php?f=\text{area of walls and ceiling}=1410)
therefore, the area of walls and ceiling is 1410 square meters.
given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,
![\text{ the total painting cost}=10*(\frac{1410}{25})](/tex.php?f=\text{ the total painting cost}=10*(\frac{1410}{25}))
![\text{ the total painting cost}=10*56.4=564](/tex.php?f=\text{ the total painting cost}=10*56.4=564)
therefore, the total painting cost is $564.
tiles will be required for floor. let us find the area of floor.
![\text{area of floor} = 40*3\text{ square meters}](/tex.php?f=\text{area of floor} = 40*3\text{ square meters})
![\text{area of floor} =120\text{ square meters}](/tex.php?f=\text{area of floor} =120\text{ square meters})
given: 1m squared floor tiles costs $3. so,
![\text{total cost for tiles} = 3*120 = 360](/tex.php?f=\text{total cost for tiles} = 3*120 = 360)
therefore, the total tiles cost is $360.
now let us find combined total cost of tiles and paint.
![\text{combined total cost}= 564+360 = 924](/tex.php?f=\text{combined total cost}= 564+360 = 924)
therefore, the combined total cost of tiles and paint is $924.