4x^2+8x-12 in vertex form

y = 4 (x + 1)² - 16

Step-by-step explanation:

Step 1: Equation at the end of step 1

(2²x²+8x)-12

Step 2:

Step 3: Pulling out like terms

Pull out like factors :

4x² + 8x - 12  =   4 • (x² + 2x - 3)

Trying to factor by splitting the middle term

Factoring  x²+ 2x - 3

The first term is,  x²

its coefficient is  1 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  -3  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -3 = -3  

Step-2 : Find two factors of  -3  whose sum equals the coefficient of the middle term, which is   2 .

   -3    +    1    =    -2  

     -1    +    3    =    2    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -1  and  3

x² - 1x + 3x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-1)

             Add up the last 2 terms, pulling out common factors :

                   3 • (x-1)

Step-5 : Add up the four terms of step 4 :

                   (x+3)  •  (x-1)

            Which is the desired factorization

Final result :

Final result :

 4 • (x + 3) • (x - 1)

Now convert to vertex form:

y = 4 (x + 1)² - 16

the correct answer to your question is a. 4^4

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