One pool contained 100 liters of water and the other 150 liters. If 15 liters of water were added to the first reservoir and 5 liters to the second reservoir every hour, how many hours later will the water in the first reservoir be larger than the water in the second reservoir?

i dont know

step-by-step explanation:

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answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

c

step-by-step explanation: